Tip:
Highlight text to annotate it
X
hi guys
today we're going to find the length of a pendulum
that has a period of 1.3 seconds.
So, our only given in here is 1.3 seconds
which is our period and from last night's
video we know that the period of a pendulum
T equals 2 pi square root of
L/g and says we're trying to find the lenght
are going to solve for L
So, to solve for L in this equation. First we need to
to divide both sides
by 2 pi, that cancels out in there
and then we need to get rid of that square root so we need to square
both sides and that gets rid of my square root
now let's clean this up a little bit
so L is
T squared over 4 pi squared
and now since the g
dividing we need to multiply both sides by g
and now that we have our formula solved for
L we can figure out the calculated answer
so
L is 0.419
and since our problem has
1.3 seconds which has 2 sig figs
our final answer also needs to have 2 sig figs so
L ends up being 0.42m
Okay I hope this video was useful
and I will see you later. Bye!