Swl11e1 - Basic arithmetic - Finding volume

In this example were asked to find the volume for each of the given shapes. So in the first one Part A, what we have to assume here is that we have a cube because we really don't have enough information otherwise. So I'm going to fill in the links of the sides here that are missing and then for volume we're going to use length times width times height which in this case is the same, so it's 4 times 4 times 4. 4 times 4 is 16 so we'll do this one first, and then 16 times 4 is 64 so our volume is 64 and we're going to have cubic inches. In our second example here we're going to need to draw and label a box. it's always nice to have a diagram sometimes the three-dimensional ones are kind of hard to draw, so just do your best. So I'm going to say and it's not really going to be to scale but it's just so I can keep track. If this is 2 feet here, this is not really 3 feet but just an illustration here okay. So we have 2 feet, 3 feet, 2 and 1/2 feet. Our volume again is going to be the length times width times height. Let's put all of our numbers in. So 2 times 3 times 2 and 1/2, that's going to be 6 times, let's write this as an improper fraction, so that's 5/2. If I work with this multiplication that's going to be 6 times 5 is 30/2 which is 15. so my volume than for this box is 15, and we can write feet cubed or we can say volume equals 15 and write it this way cubic feet. Either way is correct.