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X
Well, let's fill out what was given.
We know the initial x velocity is 50.
X acceleration is 0 as it almost always is.
And the y acceleration is 10.
Δy is just the height the object is going to move vertically--100 m.
The initial velocity in the y direction is 0,
because it's only moving horizontally. It's not moving vertically at all.
We can use this equation to plug in these variables,
and when we do that we get a value for t of 7.1 seconds,
which is also the time over here.
Again, making our appropriate substitutions,
using this equation we find a final y velocity of 71 m/s.
What about the x?
Well, If I know the initial x velocity and there's no acceleration--
that is, the x velocity isn't changing--
the final x velocity has to be exactly the same--50 m/s.
Using this equation and plugging in the appropriate values, I find a Δx of 355 m.
If you got this right on your first try, I am very impressed.
If you didn't, go back and try it again.
If you're still confused, go to the forums and I'll be there
along with a bunch of your classmates to help you out.