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For SeCl4 we have 34 valence electrons.
Se is the least electronegative, we'll put that in the center
and then put the chlorines around it.
We have 34 counts electrons. We'll put two
between atoms to form chemical bonds. We've used eight valence electrons.
And then we'll go round the outside
and fill the octet for the chlorines or until we use all 34 valence electrons.
We have 8, 10,
and 32 valence electrons.
So we've used 32 valence electrons and the octets are completed for all the atoms.
But we have 34 valence electrons for the SeCl4 Lewis structure.
We'll place those remaining two valence electrons
on the central Se atom like this.
So at this point we've used all 34 valence electrons
Each of the chlorine atoms has eight valence electrons so the octets are
satisfied for the chlorines.
The selenium it has 10 valence electrons
that's okay though because Se is below row two,
period two, on the periodic table and you can have an expanded octet.
So it has 10 valence electrons but that's okay.
This is the Lewis structure for SeCl4
and this is Dr. B. Thanks for watching.