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Hi today i'm gonna show you an reaction between potassium nitrate and sugar.
Potassium nitrate (KNO3) is used as oxidizer and the sugar (C12H22O11) is used as reductor.
The ratio KNO3/C12H22O11 here is around 3:2 and there're two types of reactions that happen.
Reaction 1: 48 KNO3 + 5 C12H22O11 --> 24 K2CO3 + 24 N2 + 55 H2O + 36 CO2
Reaction 2: 24 KNO3 + C12H22O11 --> 24 KNO2 + 12 CO2 + 11 H2O
Which one occur more depends on how well it's mixed and which one is in excess.
Well lets watch the reaction.
You can see a violet flame. This is recognizable for the potassium particle.
Some reaction products have formed. This can be either KNO2 as K2CO3.
You see a more yellowish substance in front of the plank. This is KNO2.
And here you see a white substance which is K2CO3.
Where KNO2 has formed KNO3 was in excess, and where K2CO3 has formed the sugar was in excess.
I hope you liked it.