Tip:
Highlight text to annotate it
X
in this example we are required to find the ratio of binding energies of electron in n
equal to 2 of hydrogen atom and n equal to 3 of triply ionized berkelium atom , now in
solution we can write we can write that binding energy of, an electron . in a hydrogenic atom.
in . n-ath orbit , is given as – this can be written as binding energy in n-ath orbit
of electron we can write as – 13.6 multiplied by z square by n square electron volt.
this is the amount of energy which when supplied to electron its total energy should be equal
to 0 , now, for hydrogen atom. we are required to find, for n equal to 2 so we can write-
binding energy of hydrogen atom in n equal to 2 electron we can write as 13.6 multiplied
by 1 by 2 square. that is 13.6 by 4 that is 3.4 electron volt .
similarly for, beryllium + 3 . in n equal to 3 . we calculate the binding energy for
the electron of this beryllium for this + 3 - this can be written as – 13.6 multiplied
by , z we can substitute as 4, so here this will be . 4 square divided by 3 square , so
this can be written as , 13.6 multiplied by, 16 by 9 that is, 24.18 electron volt.
and if we calculate the ratio of binding energy of hydrogen in n equal to 2 to binding energy
of beryllium in n equal to +3 orbit , this can be written as – 3.4 divided by 24 point.
1 8, on simplifying we get 0.14 - this will be the answer to this problem.