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First we look at our given table: Mass= 300 kg
Force of gravity= 9.8 m/s^2 Coefficient of friction= 0.80
Force of friction= ?
Note: We see that the normal force (Fn) and the
force of gravity (Fg) are balancing each other out since the dragster is not moving up or
down, but horizontally. Allowing the Force of friction (Ff) between the tires of the
dragster and the asphalt.
The equation that we will be using is Force of friction = coefficient of friction x normal
force.
Remember that the normal force is equal to the Force of Gravity which equal's mass x
gravity. So our eqauation changes to Force of friction
= coefficient of friction x mass x gravity.
This gives us a Force of friction of 2353 Newtons (N), which is simplified
to 2.4x10^3 N.